Calculate how much surface area/volume of water

  • Thread starter Thread starter tgn
  • Start date Start date
  • Tags Tags
    Surface Water
AI Thread Summary
To calculate the surface area and volume of water needed to push a column of water to a specific height, the concept of hydrostatic equilibrium is essential. The pressure exerted by a water column is directly related to its height and not concentrated based on surface area differences. A common misconception is that larger surface areas can create higher water levels in connected systems; however, water will only rise to the level of the source tank. Understanding these principles is crucial for designing an effective sump from acrylic. Accurate calculations will ensure the correct dimensions for submerged and dry chamber areas.
tgn
Messages
3
Reaction score
0
does anyone have a formula or a good link to show how to calculate how much surface area/volume of water it takes to push (from the bottom) a column of water of a certain width to a certain height. I'm trying to make my own sump out of acrylic and i need to know this to get the dimension right so that i'd know exactly how much of the first chamber will be submersed in water and how much wil be dry. thanks,
:confused:
 

Attachments

  • untitled.JPG
    untitled.JPG
    7.9 KB · Views: 532
Physics news on Phys.org
Well have you tried using the concept of hydrostatic equilibrium? Try writing an equation relating the atmospheric pressure with the height of the water column.

Cheers
mav
 
maverick280857 said:
Well have you tried using the concept of hydrostatic equilibrium? Try writing an equation relating the atmospheric pressure with the height of the water column.

Cheers
mav
heheh yeah i was hoping someone would tell me what the formula or relationship is though, as I'm not a physics major, do recall doing this kind problem in general physics though.
 
It sounds like you have a common misconception about pressure: pressure doesn't get concentrated. If you take a container of any size, fill it with water and attach a hose to the bottom, the water in the hose will rise no higher than the level of the water in the tank.
 
russ_watters said:
It sounds like you have a common misconception about pressure: pressure doesn't get concentrated. If you take a container of any size, fill it with water and attach a hose to the bottom, the water in the hose will rise no higher than the level of the water in the tank.
oh... i guess I'm wroing, I've always thought with the larger surface area on 1 side and a small surface area on the other, water on the smaller side will rise to a higher level due to pressure downward on the other side with the larger surface area..
thanks for the correction
 
russ_watters said:
It sounds like you have a common misconception about pressure: pressure doesn't get concentrated. If you take a container of any size, fill it with water and attach a hose to the bottom, the water in the hose will rise no higher than the level of the water in the tank.

Well looking sleepily at the diagram, I though this was a problem involving pressure. Did you get it to work tgn?

cheers
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top