Calculate Magnetic Field of Moving Magnetic Dipole

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SUMMARY

The discussion focuses on calculating the magnetic field of a uniformly moving magnetic dipole with a magnetic dipole moment \(\vec{M}\) aligned with its direction of motion. The formula for the magnetic field of a magnetic dipole is provided as \(\vec{B}=\frac{\mu_0}{4\pi} [\frac{ 3\hat{r}(\hat{r}\cdot\vec{M})-\vec{M} }{ r^3 }]\). The user applies the Lorentz transformation to derive the magnetic field in the moving frame, resulting in \(\vec{B}'=\frac{\mu_0 m \gamma}{4\pi r^4}[3x\hat{r}-r\hat{x}+\frac{\gamma \beta \hat{x}}{\gamma+1}(\frac{3x^2}{r}-r)]\). The user questions the necessity of the Lorentz transformation and considers alternative methods for calculating the force on a conducting circular loop placed in front of the moving dipole.

PREREQUISITES
  • Understanding of magnetic dipole moments and their properties
  • Familiarity with the Lorentz transformation in electromagnetism
  • Knowledge of the Biot-Savart law for magnetic fields
  • Basic principles of electromagnetism and forces on conductors
NEXT STEPS
  • Research the application of the Biot-Savart law to moving charges
  • Study the implications of electromagnetic induction on conducting loops
  • Explore alternative methods for calculating fields of moving charges
  • Learn about the effects of relativistic speeds on electromagnetic fields
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Physicists, electrical engineers, and students studying electromagnetism, particularly those interested in the dynamics of magnetic fields and forces on conductors in motion.

ShayanJ
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Does anyone know how to calculate the magnetic field or flux of a uniformly moving magnetic dipole with magnetic dipole moment [itex]\vec{M}[/itex] pointing along the direction of motion?
Thanks
 
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If the contribution from its motion is relevant, I think I would calculate it in its rest frame, and apply a Lorentz transformation on this field.
 
Here's the formula for the magnetic field of a magnetic dipole:
[itex] \vec{B}=\frac{\mu_0}{4\pi} [\frac{ 3\hat{r}(\hat{r}\cdot\vec{M})-\vec{M} }{ r^3 }][/itex]
And the Lorentz transformation of the magnetic field(in the absence of an electric field) is:
[itex] \vec{B}'=\gamma\vec{B}-\frac{\gamma^2}{\gamma+1}\vec{\beta}(\vec{\beta}\cdot\vec{B})[/itex]
Now putting [itex]\vec{M}=M\hat{x}[/itex] and [itex]\vec{\beta}=\beta\hat{x}[/itex],I got the following:
[itex] \vec{B}'=\frac{\mu_0 m \gamma}{4\pi r^4}[3x\hat{r}-r\hat{x}+\frac{\gamma \beta \hat{x}}{\gamma+1}(\frac{3x^2}{r}-r)][/itex]
Is everything OK with my calculations?
And one other thing...I'm going to show this result to some people who are not aware of the Lorentz transformation of the electromagnetic field.Also the question is from somewhere which makes me almost sure that there should be another way other than using the Lorentz transformation for the field.But I can remember no other way!
So maybe the motion doesn't matter!
The question is asking that if one places a conducting circular loop in front of such a moving magnetic dipole,perpendicular to its direction of motion,what will be the force opposing the motion of the dipole?
 

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