Calculate magnetic potential of a given current density

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TheBlueDot
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Hello,

I'm current studying magnetostatics and I'm struggling to understand the equation for A. Here is the equation from Griffith in the attachment. My confusion is, if the object is a cylinder and the current density is a function of s, J(s), then how would I write r-r'?

Thank you!
 

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Since it is magnetostatics, everything is static and we can ignore the t and t'. What it says is that A at the point [itex]\vec{r}[/itex] is given by adding up all of the currents [itex]\vec{J}(\vec{r'})[/itex] at all points [itex]\vec{r'}[/itex] and dividing by the distance between [itex]\vec{r}[/itex] and [itex]\vec{r'}[/itex] Exactly how you write this depends on where the currents are flowing. When you say J(s), what is s? Do you mean a cylinder where current is only flowing on the surface of the cylinder?
 
Hi phyzguy,

Thank you for replying.
For the problem I'm looking at, J(s) = ks, where k is a constant and s is the radius of the cylinder.
With that J(s), I got $$A = \frac {\mu_{o}} {4\pi}\int \frac{a*s(sdsd\phi dz)}{s}\hat{z}$$. Is this correct?
 
TheBlueDot said:
Hi phyzguy, Thank you for replying.
For the problem I'm looking at, J(s) = ks, where k is a constant and s is the radius of the cylinder.
With that J(s), I got $$A = \frac {\mu_{o}} {4\pi}\int \frac{a*s(sdsd\phi dz)}{s}\hat{z}$$. Is this correct?

No, you're still missing a couple of things. First, what is the direction of J? Is it in the z direction as you have indicated, or is it in the φ direction? Second, A is a function of the position vector [itex]\vec{r}[/itex]. You haven't included [itex]\vec{r}[/itex] anywhere. Note you need two position vectors, [itex]\vec{r'}[/itex] which describes the current distribution, and which you have replaced by s, but you also need the second position vector [itex]\vec{r}[/itex] which describes where you are calculating A. Also, you need limits on your integration. Does s run from 0 up to some R? What about the limits on φ and z?