Calculate Momentum/KE Transfer in Neutron-Boron Collision

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In a neutron-boron collision scenario, a neutron with a mass of 1.67×10^−27 kg and speed of 45000 m/s collides with a stationary boron nucleus of mass 1.66×10^−26 kg. To determine the fraction of kinetic energy transferred to the boron nucleus in a perfectly elastic collision, the conservation of momentum and kinetic energy equations are applied. The challenge arises from having two unknowns, leading to the need for simultaneous equations. Substitution methods or the quadratic formula may be required to solve for the final velocities. This approach will yield the desired fraction of kinetic energy transferred.
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A neutron with a mass of 1.67×10^−27 kg and moving with a speed of 45000 m/s makes a head-on collision with a boron nucleus with a mass of 1.66×10^−26 kg. The boron nucleus is originally at rest.

If the collision is perfectly elastic, what fraction of the neutron's original kinetic energy is transferred to the boron nucleus?
 
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What equations apply? You need to show your work before we can offer tutorial help.
 
I used the conservation of momentum equation, M neutron * Vi,n = M neutron * Vf,n + M boron * Vf,b

Then I would use the KE equation .5(M neutron)(Vi,n)^2 = .5(M neutron)(Vf,n)^2 + .5(M boron)(Vf,b)^2

However, I realized that I would be messing with two unknowns and I have no idea how to approach that, unless I'm totally off with the equations I presented.
 
You indeed have two unknowns, but you also have two equations, which you can solve simultaneously.
 
Ah... Ok, I guess I have to do some kind of substitution.
 
richylai said:
Ah... Ok, I guess I have to do some kind of substitution.
That would be the way forward... :smile:
 
Oh no... Looks like I have to use the quadratic formula for this... -.-'
 
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