Calculate position of plate between two fluids

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SUMMARY

The discussion centers on calculating the position of a plate between two fluids, with a final answer of 4.59 mm. The key equations used include the shear stress equation, τ = μ(du/dy), and the relationship between the shear stresses of the two fluids, expressed as μ1(du/dy1) = μ2(du/dy2). The user derives the position of the plate by substituting variables into the equation, ultimately finding y1 = 3.31 mm. However, there is contention regarding the assumption that the shear stress exerted by both fluids on the plate is equal, suggesting the problem may be under-specified.

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  • Understanding of fluid mechanics principles, specifically shear stress and viscosity.
  • Familiarity with the equations of motion in fluid dynamics.
  • Knowledge of how to manipulate algebraic equations to solve for unknowns.
  • Experience with interpreting and solving engineering problems involving multiple fluid interfaces.
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  • Review the principles of shear stress in fluid mechanics.
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bill222
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Homework Statement


Problem is as shown in the picture.
djA3Hjh.png

The answer is meant to be a 4.59mm.

Homework Equations


Tau=mu(du/dy)

The Attempt at a Solution


Force (tau) acting on plate from both fluids is equal, as is velocity (du).

mu1 (du/dy1) = mu2 (du/dy2)

mu1/dy1 = mu2/dy2
(mu2/mu1) *y1 = y2

y1 + y2 + plate thickness = width
y1 + y2 + 0.7937 = 12.7 mm

By substituting in mu2/mu1 *y1 = y2 I obtain the answer y1 = 3.31 mm.Any help is much appreciated
 
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Who says that the force (or shear stress) exerted by each fluid on the plate has to be the same? It seems to me this problem is under-specified.
 

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