Calculate Power to Stop 32.0kg Wheel in 15s

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To calculate the average power required to stop a 32.0 kg wheel rotating at 280 rev/min in 15 seconds, the approach involves using the torque equation τ = Fd, where F is the force and d is the radius of the wheel. The user seeks clarification on the acceleration (a) using ωf = ωi + αt and is unsure if the distance (d) refers to the wheel's radius of 1.20 m. Another suggested method involves calculating the initial rotational energy and determining average power as the change in energy over time. The discussion also highlights the need to calculate the moment of inertia for the wheel to find the rotational energy. Understanding these concepts is crucial for solving the problem effectively.
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A 32.0 kg wheel, essentially a thin hoop with radius 1.20 m is rotating at 280 rev/min. It must be brought to a stop in 15.0s
What ist the required average power to do this?

I know that P=τω
To find τ I used the equation τ=Fd where F=ma I figured I would find a by using the equation ωf= ωi + αt
First off is this the right approach? I'm also confused as to what d is. My book doesn't really explain it that well, would d be = 1.20m?

Thanks for any help
 
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Another way to approach this problem is to calculate the initial rotational energy, then the average power is just delta-E / delta-t

What is the rotational E in terms of the moment of inertia and rotational velocity? How do you calculate the moment of inertia for the wheel as described?
 

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