Calculate resistance of circuit (in series and parallel)

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The discussion focuses on calculating the resistance, voltage drop, and current flow in a circuit with both series and parallel components. The user attempts to calculate the resistance of various lamps using the formulas R = V/I and P = I*V, but expresses confusion regarding the application of these concepts, especially in series circuits. Clarifications are provided on how to determine the equivalent resistance of bulbs based on their power ratings and operating voltages. Key points include that in series circuits, the total voltage is the sum of individual voltages, while in parallel circuits, all branches share the same voltage. The conversation emphasizes the importance of understanding these principles to accurately solve the circuit problem.
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Homework Statement


I am a maths tutor - so physics is not my forte. One of my students asked for help regarding this question - it's been 4 years since I've used any of these calculations, and I don't have access to a textbook and so I desperately need some help. I have attached a copy of the circuit.
Question: a)Calculate the resistance of each lamp. b)Calculate voltage drop across each component, and current flow at each point between component. c) total power that the circuit is using.


Homework Equations


I=P/V and R=V/I


The Attempt at a Solution


Lamps c&d...
I=15/12=1.25 thus R=12/1.25=9.6?

Lamp e...
I=10/12 R=14.4

Lamp f
I=5/12 R=28.8

Thus as in parallel, 1/R(t)= 1/R(1) + 1/R(2)...
=1/9.6+1/9.6+1/14.4+1/28.8
1/R(t)=16/5
R(t)=3.2

Is this at all correct?

The series circuit confuses me though - can anyone help?
 

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If I is current, V is voltage in Volts, R is resistance in Ohms, P is power (in Watts), then the following hold for a given component:

V = I*R
P = I*V = I2*R = V2/R

Given the wattage ratings of each lamp and their given rated voltages, you can determine their resistances. If no rating is specified but the circuit indicates a wattage and the voltage is obvious, use those to find resistance.

Resistances in series add as Rtotal = R1 + R2 + R3 + ...
 
is the voltage obvious though? doesn't it change in a series circuit? But as the question gave the voltage for each lamp - is this the value I use?

Sorry but your reply wasn't very helpful - it just stated lots of facts which don't help if I am having trouble applying them - can you be more specific to the question?
 
MathsTutor said:
is the voltage obvious though? doesn't it change in a series circuit? But as the question gave the voltage for each lamp - is this the value I use?

Sorry but your reply wasn't very helpful - it just stated lots of facts which don't help if I am having trouble applying them - can you be more specific to the question?

I figured that just a little memory jog would be all that you needed, if as you say, you've done these sorts of problems in the past. I can do more detail.

When you see a light bulb designated 12V/24W on a schematic, it generally means that this bulb is designed to operate at 12V and will consume 24W at that voltage. However, this doesn't mean that it is being used that way in a given circuit. It's just the "part rating" for the bulb.

What you can do with that rating is determine the equivalent resistance of the bulb (we're assuming here that the resistance doesn't vary with operating voltage of the bulb. Not a particularly good assumption for 'real life' bulbs, but it's typical of these theoretical problems). The equivalent resistance to assign to the 12V/24W bulbs is found using the relationship between power, voltage, and resistance; P = V2/R.

For the bulbs c,d,e,f, they are all operating directly from the voltage supply. Since no voltage rating is supplied for the bulbs we assume that the supply voltage is their intended operating voltage, and that they will in fact be consuming 15,15,10, and 5 watts respectively. Given the operating voltage, you can turn each of those wattages into a current value via P = I*V.

The circuit contains two types of subcircuit. One is a serial branch consisting of two bulbs and a resistor. The other is a set of parallel branches with a single light bulb in each.

The characteristics of each type of subcircuit are as follows:

Series circuit:
1. All series components have the same current flowing through them.
2. The voltage across the series branch is equal tot he sum of the voltages across its individual components.

Parallel circuit:
1. All branches have the same voltage across them.
2. The total current drawn by the parallel circuit is the sum of the currents through each branch.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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