Calculate Satellite Gain: Earth-to-Sphere Ratio

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The discussion focuses on calculating the gain of a geosynchronous satellite using the formula derived from the Earth's cross-sectional area and the surface area of a sphere at the satellite's altitude. The radius of the Earth is approximately 6400 km, and the satellite orbits at 36,000 km. The book states that satellite antenna gain is the inverse ratio of the Earth's cross-sectional area to the sphere's surface area, assuming 100% efficiency. However, a participant points out that the cross-sectional area should be calculated as πR², not 4πR², as it represents a slice through the center of the sphere. This clarification is essential for accurately determining the satellite gain.
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This is not a connection. I just want ot know how they dervied this formula from gain

Consider a geosynchronous satellite whose global beam covers all of the visible Earth's surface. The radius of the Earth is about 6400km, and the altitude of the satellite is 36,000km.

How would you work out the gain of the satellite?

Book has :Satellite antenna gain, relative to the isotropic antenna situation, is equivalent to the inverse ratio of the cross-secitonal area of the Earth to the surface area of a sphere at 36,000km, assuming 100% effeciency.

Solution has \frac{4pi R^2}{pi R^2}

numerator is for satellite and denominator is for earth






The Attempt at a Solution


 
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hi bos1234! :smile:
bos1234 said:
Book has :Satellite antenna gain, relative to the isotropic antenna situation, is equivalent to the inverse ratio of the cross-secitonal area of the Earth to the surface area of a sphere at 36,000km, assuming 100% effeciency.

the cross-sectional area of the Earth isn't the area of the whole sphere, it's only the area of a slice through the centre of the sphere, so it's only πR2 instead of 4πR2 :wink:
 
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