Calculate Speed and Time to Revolve Around the Moon

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To calculate the speed of a command module orbiting the Moon at an altitude of 60 miles, the formula Vcm^2 = G * Mm/Ro is used, resulting in a speed of approximately 1.679 meters per second. The radius of the orbit (Ro) is determined by adding the Moon's radius to the altitude, yielding 1.74E6 + 96540 meters. To find the time for one complete revolution, Kepler's third law can be applied using the formula P = 2π√(a^3/μ), where 'a' is the orbital radius and 'μ' is the gravitational parameter. The gravitational parameter is calculated as G multiplied by the mass of the Moon. This approach provides a systematic method for determining both speed and orbital period.
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if the command module is 60 miles above the surface of the moon it wants me to calculate the speed of the module adn the time it takes to complete one revolutionaround the mooon?
givens

mass moon = 7.35 * 10 to the 22 power
radius moon = 1.74 * 10 to the 6 power
altitude above the surface of the moon = 60 miles

converted the 60 miles to meters which was 96540 m

Ro = Rm + h
Ro = 1.74E6 + 96540
Ro = 1.74E22

Vcm is the command module

Vcm^2 = G * Mm/ro
Vcm^2 = 6.673E-11 * 7.35E22/1.74E22
Vcm = 1.679 meters/sec

and not sure if this is right and don't know what to use to figure out the time it took to make 1 revolution

thanks
 
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on the time part of it should i use kelpters law?
 
Period can be found by using this formula:

<br /> <br /> P = 2\pi \sqrt{\frac{a^3}{\mu}}}<br /> <br />

Where a is the semimajor axis (the radius for circular orbits, like your problem)
and mu is the gravitational parameter, or G*M
 
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