Calculate Tension in Cable for 225 kg Square Sign Hanging from 3.00 m Rod

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To calculate the tension in the cable supporting a 225 kg square sign from a 3.00 m rod, the forces and torques acting on the system must be analyzed. The sum of horizontal forces (Fx), vertical forces (Fy), and torque must be considered, even without knowing the angles initially. The geometry indicates that the cable forms a right triangle with the wall and the rod, allowing the angle to be determined using arctan(4/3). This angle is crucial for resolving the tension into its components and solving for the tension in the cable. Understanding these principles will aid in accurately calculating the tension required to support the sign.
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A 225 kg uniform square sign, 2.00 m on a side, is hung from a 3.00 m rod of negligible mass. A cable is attached to the end of the rod and to a point on the wall 4.00 m above the point where the rod is fixed to the wall. What is the tension in the cable?
I know I need to use:
sum of Fx
sum of Fy
sum of Torque

What I'm wondering is how should I do this when I don't know any angles whatsoever? Any help on this would be useful, just knowing this should get me through the problem.
 
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bearhug said:
A 225 kg uniform square sign, 2.00 m on a side, is hung from a 3.00 m rod of negligible mass. A cable is attached to the end of the rod and to a point on the wall 4.00 m above the point where the rod is fixed to the wall. What is the tension in the cable?
I know I need to use:
sum of Fx
sum of Fy
sum of Torque

What I'm wondering is how should I do this when I don't know any angles whatsoever? Any help on this would be useful, just knowing this should get me through the problem.
The rod is 3 m and the cable is attached 4 m up from the wall. Now if the sign was just a point load at the end of the rod, the angle would be arctan 4/3, correct?
 
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