Calculate the amount of heat supplied to a gas

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Homework Help Overview

The discussion revolves around calculating the amount of heat supplied to a multatomic gas during a temperature increase of 100K under conditions described as free expansion. The original poster expresses uncertainty about how to approach the problem and mentions a specific answer of 3320kJ.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants question the definition of free expansion and its implications for the problem. There is discussion about whether the expansion occurs against a vacuum or a constant pressure. Attempts to derive the molar heat capacity from the given information are explored, along with the relationship between heat, temperature change, and the number of moles.

Discussion Status

Participants are actively engaging with the problem, exploring various interpretations of the conditions and attempting to derive necessary values. Some guidance has been offered regarding the relationship between heat capacity and the specific gas type, but no consensus has been reached on the correct approach or definitions.

Contextual Notes

The original poster has limited information, only providing the temperature change and the amount of gas. There is uncertainty about the specific heat capacity for the multatomic gas and how it relates to the problem at hand.

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Homework Statement


1kmol of multatomy(I hope you understand - gas with many atoms) gas is heated for 100K (conditions of free expansion). I have to calculate the amount of heat supplied to gas. I have no idea how to do it. The right answer is 3320kJ

Homework Equations

The Attempt at a Solution

 
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What is your definition of free expansion conditions?
 
Chestermiller said:
What is your definition of free expansion conditions?
I do not have any definition. It is said in the task. I guess it means, there is nothing influencing the expansion of gas.
 
MisterP said:
I do not have any definition. It is said in the task. I guess it means, there is nothing influencing the expansion of gas.
Usually, free expansion is defined as expansion into a vacuum. However, I don't think that is what was intended here. I think what was intended here is expansion against a constant pressure equal to the initial pressure of the gas. If that were the case, then the amount of heat supplied would be equal to the change in enthalpy of the gas. This is given by $$Q=\Delta H=nC_p\Delta T$$where n is the number of moles and ##C_p## is the molar heat capacity of the gas. Are you given no information about the gas? If not, from the answer they gave, what is the molar heat capacity of the gas?
 
Chestermiller said:
If not, from the answer they gave, what is the molar heat capacity of the gas?
There is nothing more.. Just the temperature - 100K (how much it was risen) and 1kmole, that`s it.. Maybe the fact that it is multi-atom gas changes something?
 
MisterP said:
There is nothing more.. Just the temperature - 100K (how much it was risen) and 1kmole, that`s it.. Maybe the fact that it is multi-atom gas changes something?
Not really. What do you calculate for Cp? That might tell us something.
 
I really do not know.. :(
Edit: or c = Q / (mΔT). ??
But that won`t help..
 
MisterP said:
I really do not know.. :(
Edit: or c = Q / (mΔT). ??
But that won`t help..
Let's see the number you get using their answer.
 
I do not get it. I have not been solving these types of tasks since I was in high school, that's around 13 years ago and now they through all the themes on basic physics and I have to solve this "easily" they say ..
 
  • #10
MisterP said:
I do not get it. I have not been solving these types of tasks since I was in high school, that's around 13 years ago and now they through all the themes on basic physics and I have to solve this "easily" they say ..
Dues the equation I wrote make sense to you? What course is this for?
 
  • #11
We had 3 day course on physics - starting mechanics, energy, oscilations, molecular physics, thermodynamics, electrics. I am studying electric engeneering and so, there is this fast course on physics, just for a check. I do understand Your formula, but I do not have Cp.
 
  • #12
MisterP said:
We had 3 day course on physics - starting mechanics, energy, oscilations, molecular physics, thermodynamics, electrics. I am studying electric engeneering and so, there is this fast course on physics, just for a check. I do understand Your formula, but I do not have Cp.
We are trying to "back out" the value of Cp from the answer they gave to see if we can make any sense out of it.
 
  • #13
So, I found this. E = x*n*R*T
If x = 4, then I get right answer, but I do not know if this is right. But I have seen that x is 3.
n - moles
R - 8.3 constant
T - temperature

Edit: x = i/2+1
i = 6 for multi atomic gases, so that is how to get 4 and seems like this formula works :)
 
Last edited:
  • #14
MisterP said:
So, I found this. E = x*n*R*T
If x = 4, then I get right answer, but I do not know if this is right. But I have seen that x is 3.
n - moles
R - 8.3 constant
T - temperature

Edit: x = i/2+1
i = 6 for multi atomic gases, so that is how to get 4 and seems like this formula works :)
Very nice.

This is pretty much where I was trying to get you to head (although you didn't appear to want to participate), except the equation should be the same as in my post #2 with ##C_p=xR##.

For oxygen and nitrogen, x = 3.5 and i=5, and for carbon dioxide, x = 4.4 and i is about equal to 7. So I guess, in your source, they assign generic values of x = 4 and i = 6 to what they call a generic polyatomic gas.
 
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