Calculate the Electric Field at the given point

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SUMMARY

The discussion focuses on calculating the electric field generated by a -12 nC charge located at the origin, specifically at the point (-5.0 cm, -5.0 cm). The correct unit vector for this position is derived as -1/√2(î + ĵ), indicating that the electric field vector points away from the charge. The participants clarify the conversion of the vector components into unit vectors, emphasizing the importance of directionality in electric field calculations.

PREREQUISITES
  • Understanding of electric field concepts and vector notation
  • Familiarity with Coulomb's Law and charge interactions
  • Knowledge of unit vectors and their calculation
  • Basic algebra and geometry for vector components
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  • Learn about vector normalization and unit vector calculations
  • Explore the concept of electric field lines and their representation
  • Investigate the effects of multiple charges on electric field calculations
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Homework Statement


A -12 nC charge is located at the origin.

What is the electric field at the position (x2,y2)=(−5.0cm,−5.0cm)? Write electric field vector in component form.

Homework Equations


upload_2014-9-27_11-44-48.png


The Attempt at a Solution


Here, r^2 = (-0.05 - 0 )^2 meters squared. q=-12*10^-9 C.
For the unit vector, I chose \hat{i} and \hat{j} for the horizontal and vertical components of the vector. In the solutions manual, they choose a unit vector \frac {1} {\sqrt{2}}. I am not sure how they chose this as their unit vector.

I think they start with unit vectors of 5*\hat{i} and 5*\hat{j} then to convert to unit vectors they divide by the magnitude of each of the vectors (which is the length of the hypotenuse; 5*\sqrt(2).

Can someone verify this, please?
 

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The point is that ##\hat r## should be a unit vector with the same direction as ##\vec r##. The vector ##\vec a = \hat i + \hat j##, this is not a unit vector since ##\vec a^2 = 2##. Additionally, ##\hat r## should be pointing away from the origin, which in (-5cm, -5cm) means that it is given by ##- \frac 1{\sqrt 2}(\hat i + \hat j)##.
 

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