The problem involves calculating the focal length of a spectacle lens needed to correct hyperopia for a person with a near point of 1.10 m, compared to the normal near point of 25.0 cm.
Participants are actively engaging with the problem, raising questions about the correct interpretation of the lens formula and the signs associated with image distance. Some guidance is suggested regarding the drawing of a diagram to visualize the setup.
There is a noted discrepancy between the original poster's calculated focal length and the provided answer, prompting further investigation into the assumptions made regarding image placement.
It should be on the opposite side, so q is negative,right? That would give the right answer.TSny said:In order for the person to be able to clearly see an object placed 25 cm away, where should the image of the object formed by the lens be located? Should the image be on the same side of the lens as the object?
q is negative when the image is on the same side as the object.gungo said:It should be on the opposite side, so q is negative,right? That would give the right answer.