- #1
DODGEVIPER13 said:so what you are saying is that instead of just del I should have used del f for notation?
(∂f/∂x)x+(∂f/∂y)y+(∂f/∂z)z (where x, y, and z should be x(hat), y(hat), and z(hat))
DODGEVIPER13 said:so if I am right which I probably am not then (a) 6yUx+(-0)+zUz the reason I put 0 is the the partial derivative of -2xz with respect to y is 0 correct since there is no y term.
DODGEVIPER13 said:dang I felt it might have actually been right. was it simply this 6yi+k
DODGEVIPER13 said:∇V1=(∂f/∂x)i+(∂f/∂y)j+(∂f/∂z)k= 6y i + k
DODGEVIPER13 said:∂(V1)/∂x = 6y i sorry I forgot the "i" in the previous post.
DODGEVIPER13 said:6y-2z i
DODGEVIPER13 said:(6y-2z)i + (6x)j + (1-2x)k
DODGEVIPER13 said:for V2 (10cos(phi))-z)i-(10sin(phi))j-(ρ)k
DODGEVIPER13 said:for V3 ((-2/r^2)cos(phi))i-((2sin(phi))/(r^2sin(theta)))k
DODGEVIPER13 said:for V3 ((-2/r^2)cos(phi))i-((2sin(phi))/(r^2sin(theta)))k
The gradient of a function is a vector that shows the rate and direction of change of the function at a specific point. It is calculated by taking the partial derivatives of the function with respect to each variable.
2.Calculating the gradient is important because it allows us to determine the direction of steepest ascent or descent of a function at a given point. This is useful in optimization problems and in understanding the behavior of multivariable functions.
3.The gradient of a function is calculated by taking the partial derivatives of the function with respect to each variable and then combining them into a vector. For example, if the function is f(x,y,z), the gradient would be [∂f/∂x, ∂f/∂y, ∂f/∂z].
4.The gradient vector represents the direction of the greatest increase of the function at a specific point. The magnitude of the vector represents the rate of change in that direction.
5.Yes, the gradient of a function can be negative. This would indicate that the function is decreasing in that direction at that point. A positive gradient indicates an increase, and a gradient of zero indicates no change.