Calculate the initial acceleration of this pulley system

In summary, the homework statement says "The Attempt at a Solution" and the student is trying to figure out how to solve the homework equation. They are having trouble because of the force balance equations and the fact that the pulley on the left is massless. They say that if the tension in the rope is zero, the acceleration of each mass is g. They eventually solve the problem and are done.
  • #1
Phantoful
30
3

Homework Statement


w1Gfx7r.png


Homework Equations


W=mg
F=ma

The Attempt at a Solution


I'm not sure how I should be answering this problem, and the diagram itself looks odd. I was thinking about how it would work in real life, since the biggest pulley is attached to the leftmost pulley, by the same string that m1 is on, wouldn't acceleration all be zero? Since the biggest pulley is attached to the roof...

Also, looking at it from FBD, The masses seem simple (m1*g, T1 and m2*g, T2) but when I try to do the pulleys, it's like a recursion happens because the whole system loops.
 

Attachments

  • w1Gfx7r.png
    w1Gfx7r.png
    7 KB · Views: 1,172
Physics news on Phys.org
  • #2
Phantoful said:
wouldn't acceleration all be zero
depends on m1 and m2 values !
 
  • #3
Phantoful said:
the whole system loops
not the whole sytem. Only the wire and it has a fixed length!

Sort out equations and knowns/unknowns...
 
  • #4
Did you notice the first item in the template also asks for 'all variables and given/known data'?

Make free-body diagrams
 
  • #5
Phantoful said:
(m1*g, T1 and m2*g, T2)
What do you mean by that? Are you suggesting that there are two different tensions, that one equals m1g and the other equals m2g? None of those statements are true.
 
  • #6
This is a very tricky problem. The force balance on the left massless pulley, has a force of T upwards and 2T downwards. So, for equilibrium, the tension in the rope must be zero.
 
Last edited:
  • #7
Chestermiller said:
The force balance on the left massless pulley, has a force of T upwards and 2T downwards.
Not only that, but a net force acting on a massless pulley doesn't get you any closer to determining its acceleration. It seems like force balance equations will not work for this problem.
Here is another way to look at it. Since the pulley on the left is massless, it will move either up or down to compensate for the motions of ##m_1## and ##m_2## without any opposing or assisting force at all. Are the motions of the two masses affected by any force other than gravity?
 
  • #8
tnich said:
Not only that, but a net force acting on a massless pulley doesn't get you any closer to determining its acceleration. It seems like force balance equations will not work for this problem.
Here is another way to look at it. Since the pulley on the left is massless, it will move either up or down to compensate for the motions of ##m_1## and ##m_2## without any opposing or assisting force at all. Are the motions of the two masses affected by any force other than gravity?
no. If the tension in the rope is zero, the acceleration of each mass is g.
 
  • #9
Chestermiller said:
no. If the tension in the rope is zero, the acceleration of each mass is g.
Sounds like you have just solved the problem.
 

What is the formula for calculating the initial acceleration of a pulley system?

The formula for calculating the initial acceleration of a pulley system is a = (m1g - m2g)/ (m1 + m2), where a is the acceleration, m1 and m2 are the masses of the objects on either side of the pulley, and g is the acceleration due to gravity (9.8 m/s^2).

What are the factors that affect the initial acceleration of a pulley system?

The initial acceleration of a pulley system is affected by the masses of the objects on either side of the pulley, the friction in the pulley system, and the angle at which the pulley is set up.

Can the initial acceleration of a pulley system be greater than the acceleration due to gravity?

Yes, the initial acceleration of a pulley system can be greater than the acceleration due to gravity, especially if the masses on either side of the pulley are significantly different.

How does the angle of the pulley affect the initial acceleration of the system?

The angle of the pulley affects the initial acceleration of the system by changing the direction of the applied force and by increasing the amount of friction in the pulley system, which can reduce the acceleration.

Why is it important to calculate the initial acceleration of a pulley system?

Calculating the initial acceleration of a pulley system is important because it allows us to understand the motion of the system and make predictions about the speed and direction of the objects involved. It also helps us to optimize the system for maximum efficiency and to identify any potential problems or safety concerns.

Similar threads

  • Introductory Physics Homework Help
Replies
3
Views
761
  • Introductory Physics Homework Help
Replies
15
Views
2K
  • Introductory Physics Homework Help
Replies
23
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
22
Views
3K
Replies
25
Views
2K
  • Introductory Physics Homework Help
Replies
30
Views
1K
  • Introductory Physics Homework Help
Replies
26
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
995
  • Introductory Physics Homework Help
Replies
10
Views
2K
Back
Top