Calculate the magnitude of the gravitational force

AI Thread Summary
To calculate the gravitational force on one sphere due to the other three, the gravitational force formula Fg=G(M1)(M2)/r^2 is applied. The force from the two adjacent spheres is calculated as approximately 1.04e-8 N using their distance of 0.72 m. The diagonal distance to the opposite sphere is determined to be 1.02 m, and the gravitational force from this sphere is also calculated. The next steps involve finding the x and y components of the forces from all three spheres and summing them to determine the net force's magnitude. This methodical approach allows for the accurate calculation of the gravitational force acting on the sphere.
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1. Homework Statement

Four 9.0 kg spheres are located at the corners of a square of side 0.72 m. Calculate the magnitude of the gravitational force on one sphere due to the other three.


2. Homework Equations

Fg=G(M1)(M2)/r^2

3. The Attempt at a Solution

I figured out the force the each of the two spheres perpendicular to the corner one by doing Fg=[(6.67e-11)(9)(9)]/[.72^2]=1.04e-8. then i used the pathageon theorum to find the radius to the sphere in the opposite corner of the square by doing square root of .72^2+.72^2=1.02. I am now having trouble finding the force of the two corner balls pulling at a 45 degree angle towards the middle of the square.
 
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For the 3rd force at a distance of 1.02 m... apply the force formula to get the magnitude of the force... ie Gm1m2/(1.02)^2

then what is the x-component of this force... what is the y-component of this force...

add up the x-compoents of all 3 forces.

add up the y-components of all 3 force.

then you have the x-component and y-component of the net force... get the magnitude...
 
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