How Do You Calculate the Speed of Air Over a U-Tube?

  • Thread starter Thread starter thenewbosco
  • Start date Start date
  • Tags Tags
    Air Speed
AI Thread Summary
To calculate the speed of air over a U-tube, one must consider the pressure difference created by the height of the fluid columns. The height difference of 1.25 cm needs to be converted into pressure using the density of the fluids involved. The equation should incorporate the atmospheric pressure (Po) and the pressure due to the height of the fluid (density * g * h) on both sides of the U-tube. The challenge lies in factoring the speed of the air into the pressure equation on the left side, where the air is blown. Understanding how the air's density affects the overall pressure balance is crucial for solving the problem.
thenewbosco
Messages
185
Reaction score
0
A problem i have encountered:

diagram at http://img.photobucket.com/albums/v11/biggm/dia.jpg

Here is a u-tube open at both ends partially filled with water and oil with given density is poured in the right column so the height of the oil is 5.0 cm.

i have calculated the difference in height to be 1.25 cm.
in the second picture, air motion on the right is shielded while air is blown over the left opening until the surfaces are at the same height.
i am to calculate the speed of the air taking the density of air to be
1.29kg/m^3.

I do not know how to create the equation needed to solve this.
i am thinking i need to find the external pressure minus the effect of the blown air on the left since it is less than the right which is just the external atmospheric pressure.

thanks for help on this
 
Last edited by a moderator:
Physics news on Phys.org
anyone... .
 
someone ...anyone
 
right..the equation should be the same as last time for the two depths, but how does the speed of the air factor into the Po. On the side with the shield it will be just Po + density*g*h and on the other side it will be P + density*g*h. How can i factor the air into the equation for P on the left?

it must be Po - effect of air...but how
 
Last edited:
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top