Calculate the voltage across a resistor using Thevenin's Theorem

AI Thread Summary
To calculate the voltage across a resistor using Thevenin's Theorem, it's essential to determine the state of the diode, which acts as a simple switch. The voltage across the diode (U_D) equals the source voltage (U_S) when the diode is in the ON state, allowing for simplification in calculations. A practical approach involves substituting a diode model into the circuit and analyzing it under both ON and OFF conditions to identify any restrictions that may arise. By making an initial assumption about the diode's state, one can begin solving the circuit and later verify the assumption's validity. This method helps navigate complex circuits and find the operating point of the diode effectively.
Andrei0408
Messages
50
Reaction score
8
Homework Statement
The diode in the next figure is considered ideal (i.e. works as a simple switch, being turned ON when U_D >= 0 and OFF when U_D < 0). What is the voltage U_S across R_S?
Relevant Equations
Thevenin's Theorem
I'm thinking I should apply Thevenin's Theorem to find the voltage, but I need to find I_D in order to be able to calculate U_S.
 

Attachments

  • 20210503_215754.jpg
    20210503_215754.jpg
    22.7 KB · Views: 184
Physics news on Phys.org
Andrei0408 said:
I need to find I_D in order to be able to calculate U_S.
You have been told that the diode works as a simple switch. So ##U_D = U_S## if the switch is ON -- never mind ##I_D##. Can you decide it is OFF or ON ?

##\ ##
 
One way to approach this is to substitute your diode model (a switch and a battery) into the circuit. This model has two switch states that have associated restrictions; no forward voltage across the switch when it's open and no reverse current when its shorted. Then you can just pick one state and analyze the circuit in that configuration to determine when the associated restriction is violated. That is the operating point at which the diode will switch states. You can do it with either "on" or "off" assumption, sometimes one is easier to solve than the other.

This approach is a good way to get "unstuck" when you have complex circuits and you don't know where to start. Just make an assumption and get started, but with the knowledge that you may have guessed wrong, then find out if, or under what conditions, you are right or wrong.
 
BvU said:
You have been told that the diode works as a simple switch. So ##U_D = U_S## if the switch is ON -- never mind ##I_D##. Can you decide it is OFF or ON ?

##\ ##
I'm not sure how to do that
 
Pick one and see if it leads to an inconsistency
 
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
TL;DR Summary: Find Electric field due to charges between 2 parallel infinite planes using Gauss law at any point Here's the diagram. We have a uniform p (rho) density of charges between 2 infinite planes in the cartesian coordinates system. I used a cube of thickness a that spans from z=-a/2 to z=a/2 as a Gaussian surface, each side of the cube has area A. I know that the field depends only on z since there is translational invariance in x and y directions because the planes are...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Back
Top