The problem involves calculating the width of a gutter based on its quadratic cross-section equation, where the depth is specified as 6 cm. The equation given is y = (4/11)x² - 4x + 11, with x and y representing measurements in centimeters.
The discussion is ongoing, with participants exploring different interpretations of the problem setup. Clarification has been provided regarding the assignment of x as width and y as depth, but further exploration of the solution process is still needed.
There is a noted ambiguity in the problem regarding the definitions of width and depth, which has led to varying interpretations among participants. The original poster expresses uncertainty about their initial calculations.
It's impossible to say if you won't tells us which of x, y is the width and which is the depth! I might guess that x is twice the width and y the depth, so that you need to solve the equation (4/11)x^2- 4x+ 11= 6. My guess is partly based on the fact that if x is the depth, you would only need to evaluate that (4/11)(6)^2- 4(6)+ 11 and that is too easy!Paulo2014 said:Homework Statement
The cross-section of a gutter can be represented by the quadratic:
y=4/11x^2-4x+11 where x and y are measurements in cm. Calculate the width of the gutter where the depth is 6cms.
Homework Equations
The Attempt at a Solution
my answer was 1.26cm or 12.6mm but I'm pretty sure that's wrong so could someone please explain how to work it out?