Calculate Torque in 12.2m Crane - 18kN Load, 67kN Tension

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The discussion focuses on calculating the tensions in the cables of a 12.2m crane lifting an 18 kN load and a 67 kN load. Participants are attempting to determine the torque generated by these loads and the forces acting at the pivot point. The lever arm for torque is calculated using the sine of the angles formed by the cables, with one participant providing a torque value of 71.24 kN*m. There is uncertainty regarding the direction and sign of the torque, as well as the total tension in the supporting cable T2. The conversation emphasizes the need to apply fundamental physics principles to accurately solve the problem.
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1. The 12.2m crane weighs 18 kN and is lifting a 67-kN load. The hoisting cable (tension T1) passes over a pulley at the top of the crane and attaches to an electric winch in the cab. THe pendant cable (tension T2), which supports the crane, is fixed to the top of the crane. Find the tensions in the two cables and the force Fp at the pivot.

There is a picture with this, but I can't upload it right now. The crane makes and angle of 40degrees with the cord holding the load (67 kN). T1 on the other side of the crane makes an angle of 5 degrees and T2 makes an angle of 10 degrees with the crane. I can upload a picture of this later, but this will only be possible after probably 8 tonight.


2. Torque=rT



3. I think I might have T1, 67 kN.

Please help me!
 
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5b6y5l.jpg


if that doesn't work,

http://i30.tinypic.com/5b6y5l.jpg

a rough sketch i just drew
 
You need to show us your work. I assume that the pivot point is the upper right corner of the yellow rectangle (where the boom attaches to the cab).

Hint: you probably need a more general version of the relevant equation that you listed. Hint: there are more relevant equations.
 
I drew a line of action through the point of application (the pulley at the top) and a lever arm.

lever arm = r sin 5 = 12.2m * sin 5 = 1.063m
1.063m * 67 kN = 71.24 kN*m

That's my work, but I don't know if I did it right. I'm not sure I drew the line of action right because I don't know which direction the torque is going in. Also, I don't know the sign of the torque.

As for T2, is it simply 67 kN+ 18kN?
 
OK, I will make more specific hints.

So far, you are showing a torque calculation, but it is not clear to me that you know why this calculation will help you answer the question. What principles (i.e. laws) of physics should you apply to solve this problem, and what is your reasoning for this? The important thing here is to justify why they are important, because this will tell you how to solve the problem. The rest is details.

How many forces are applied to the boom? (I count five.) Can you count them up? Where, and in what directions, are these forces applied to the boom?

BTW, I believe that you are correct about the value of T1.
 
xicedcandyx said:
I drew a line of action through the point of application (the pulley at the top) and a lever arm.

lever arm = r sin 5 = 12.2m * sin 5 = 1.063m
1.063m * 67 kN = 71.24 kN*m

That's my work, but I don't know if I did it right. I'm not sure I drew the line of action right because I don't know which direction the torque is going in. Also, I don't know the sign of the torque.

As for T2, is it simply 67 kN+ 18kN?

I'm not sure I follow, but please reconsider, keeping the following in mind.

Does a force with a specified line of action, have a moment about a point on that line of action?
 
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