To determine the volume of O2 required for the complete combustion of 152 g of C2H6 (ethane), first, the balanced chemical equation for the reaction is essential. The combustion of C2H6 produces CO2 and H2O. The molar mass of C2H6 is approximately 30 g/mol, leading to the calculation of moles as 152 g divided by 30 g/mol, resulting in about 5.07 moles of C2H6. Using the balanced equation, the required moles of O2 can be derived based on the stoichiometric ratios. Next, apply the ideal gas law, PV=nRT, where P is the pressure (100 kPa), V is the volume, n is the number of moles of O2 needed, R is the gas constant, and T is the temperature in Kelvin (292 K). After determining the moles of O2 from the combustion reaction, the volume can be calculated.