Calculate volume in combustion

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    Combustion Volume
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To determine the volume of O2 required for the complete combustion of 152 g of C2H6 (ethane), first, the balanced chemical equation for the reaction is essential. The combustion of C2H6 produces CO2 and H2O. The molar mass of C2H6 is approximately 30 g/mol, leading to the calculation of moles as 152 g divided by 30 g/mol, resulting in about 5.07 moles of C2H6. Using the balanced equation, the required moles of O2 can be derived based on the stoichiometric ratios. Next, apply the ideal gas law, PV=nRT, where P is the pressure (100 kPa), V is the volume, n is the number of moles of O2 needed, R is the gas constant, and T is the temperature in Kelvin (292 K). After determining the moles of O2 from the combustion reaction, the volume can be calculated.
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What volume of O2 (m3) is needed for the complete combustion of 152 g of C2H6 at 19.0oC and 100.0 kPa ?
 
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i found the moles of C2H6 which was 152g/30g/mol

then times that by 292 K and this is where i have trouble
 
First I would set up the balanced equation for the complete combustion reaction. Then, like you did, solve for the number of moles of C2H6, using the balanced equation, determine how many moles of O2 are needed.
then using the eqaution PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin, solve for the volume.
 
i don't know how to set it up though, please help
 
C2H6 reacts with O2, producing CO2 and H2O. Write this down as an equation and balance it.

This is true of any complete combustion...the products are CO2 and H20.
 
i got it, i balanced the equation, and used the mole ratio to find n and finally solved for volume
 
good work...if you'd like someone to double-check your calculations, post your numbers here.
 
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