Chemistry Calculate Volume of Products in NH3 + Cl2 Reaction

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The discussion focuses on calculating the volumes of gases produced in the reaction between ammonia and chlorine, using the balanced equation 2NH3 + 3Cl2 → N2 + 6HCl. Participants emphasize identifying the limiting reactant to determine the yield of products, suggesting the use of stoichiometry and the ideal gas law. There is debate about whether to assume standard temperature and pressure (NTP) for convenience, with some arguing that the problem can be solved without this assumption as long as ideal gas behavior is considered. The Principle of Atom Conservation (POAC) is mentioned as a relevant concept, but its application is debated among participants. Ultimately, the consensus is that the problem can be approached using volumes directly due to the equal conditions of the gases involved.
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Homework Statement


A mixture is completed from 15.0L of ammonia and 15.0L chlorine measured at the same conditions, these compounds react according to the following equation

2NH3(g) + 3Cl2(g) yields N2(g) + 6HCl(g)

When the reaction is completed, what is the volume of each gas? Assume the final volumes are measured under identical conditions.


Homework Equations



Maybe Avogadros law

The Attempt at a Solution



To be honest I do not know where to start
 
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Everything in this problem shares the same unit, (Liter for Volume). What you need to do is figure out which one of the two given gases is the limiting reactant, and then use that to calculate the yield of the two product gases.

You could start by taking either the ammonia or chlorine and calculating it in the ratio given by the balanced equation to the other one to find out which one is limiting (if any at all).
 
Since no conditions were specified, perhaps you can assume they are ideal gases?

For an ideal gas at standard temperature and pressure the molar volume is 22.4 L/mol. You could use this to find the moles and then you can use stoicheometry to determine each product, again converting back to liters using the molar volume.
 
Norfonz said:
Since no conditions were specified, perhaps you can assume they are ideal gases?

For an ideal gas at standard temperature and pressure the molar volume is 22.4 L/mol. You could use this to find the moles and then you can use stoicheometry to determine each product, again converting back to liters using the molar volume.

While this is not necessarily wrong, it doesn't make sense - it is like going from Washington to New York through San Francisco. Same volume of gas at same conditions contain same number of moles, so you can do calculations using volumes directly.
 
Is it possible to assume the conditions at NTP? If it is possible, then try applying POAC.
 
Pranav-Arora said:
Is it possible to assume the conditions at NTP? If it is possible, then try applying POAC.

No idea what you mean. POAC (Principle of Atom Conservation - nothing else but mass conservation) holds not only at NTP, but at every other TP parameters.
 
Borek said:
No idea what you mean. POAC (Principle of Atom Conservation - nothing else but mass conservation) holds not only at NTP, but at every other TP parameters.

I know that Borek but i asked for NTP because it will be much convinient to solve the problem if we assume the conditions at NTP.
 
Pranav-Arora said:
it will be much convinient to solve the problem if we assume the conditions at NTP.

No, the question can be easily solved - in exactly the same way - no matter what TP conditions are. The only assumption needed is that gases behave reasonably close to ideal gas.
 
Borek said:
No, the question can be easily solved - in exactly the same way - no matter what TP conditions are. The only assumption needed is that gases behave reasonably close to ideal gas.

Maybe your method is easy because i am very new to this mole concept and have learned only something about it, so i thought of applying POAC...:)
 
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I would elaborate, but it will give too much information for OP, and it would be against forum rules. We can get back to it in a week from now (if nothing changes).
 
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