Calculate Wavelength of 3.85 MeV Gamma Radiation from Technetium-99

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To calculate the wavelength of 3.85 MeV gamma radiation from technetium-99, the relevant formula is E = hc/λ, where E is energy, h is Planck's constant, and c is the speed of light. The discussion emphasizes the importance of understanding the relationship between energy and wavelength in electromagnetic waves. Participants are encouraged to reference their textbooks for foundational concepts and to clarify the meanings of the symbols in the equation. Additionally, there is a focus on the importance of unit consistency when solving physics equations. Understanding these principles is crucial for accurately determining the wavelength of the gamma radiation.
missy~needs~help
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Okay so I have this question...

A photon of gamma radiation emitted by the radioactive decay of technetium-99 has an energy of 3.85 MeV. This radiation has a wavelength of

a) 5.17x10^-26m
b) 3.23x10^-13m
c) 3.10x10^12m
d) 9.29x10^20m

Can anyone explain it...no idea how to even start it!:confused:
 
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Turn to the page on your text that first talks about energy and wavelength relationships for EM waves. Tell us what you find and how you plan to proceed.

We can't help you unless you help yourself. Please read the guidelines for posting in this forum.
 
I figure...that it has something to do with
E= hc/T
 
That's a start.

What do the various symbols in that equation represent?

And secondly what have you learned about units when it comes to solving equations?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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