Calculating Acceleration for a Car on a Circular Track

AI Thread Summary
To calculate the total acceleration of a car on a circular track with an 80m radius, the car accelerates from rest to 100 km/h in 10 seconds. The normal acceleration is determined using the formula v^2/r, while the tangential acceleration can be calculated as a = (vf - vi)/t. After finding the velocity at 8 seconds, the normal acceleration is computed, and both accelerations are combined as vectors since they are perpendicular. The final total acceleration is confirmed to be approximately 6.77 m/s². This approach effectively addresses the problem by breaking it down into tangential and normal components.
krnhseya
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Homework Statement



car is on a horizontal circular track of 80m radius and car starts from rest to 100km/h in 10 seconds. what's the magnitude a of ttotal acceleration of the car 8 seconds after start?


Homework Equations



normal acceleration = v^2/r

The Attempt at a Solution



convert v to m/s and r = 80. then i found normal acc.

i just have no clue on how to do this...class notes and book reading don't help me at all.
what are things i need to consider?
thank you
 
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there are two accelerations:
tangential, and normal.

dividing this problem into two parts might help you.
 
tangential is what's messing me up...
books says it's equal to v with dot above it (derivative)
or also equal to r*theta(with dot above as well)

i don't get what they actually mean or how to get it...
 
krnhseya said:
tangential is what's messing me up...
books says it's equal to v with dot above it (derivative)
or also equal to r*theta(with dot above as well)

i don't get what they actually mean or how to get it...

well, I am assuming here that tangential a is uniform.
Just ignore them, I guess you really don't have an equation to differentiate.

just use that simple for: a = vf-vi/t
10 seconds, and assume that it's same for 8 seconds.

I am pretty sure that this would be correct
 
Yes, you have found the acceleration. But the velocity that you use in the a = v^2/r equation must be the velocity of the car at t = 8 s, NOT at t =10 s, or Vf. You must use the acceleration you just found to find the velocity of the car at t = 8 s.

Also, the total acceleration is the vector sum of the tangential and centripetal accelerations.
 
well can i use v = vo+at ? considering that a is constant and vo is zero(?)
how can you use vector to do this problem...i don't know how to set up the vector...
no coords :(

[edit] well i can sum up and get final vectors i think...only problem is how to get normal acc. and tang acc. in vector form...
 
Last edited:
alright, here's what i have...

v = vo + at (given that vo = 0, v = 100km/h, t = 10)

i get 2.78m/s^2 as acceleration.

v = vo+2.78t (given that vo=0, t = 8)

i get v = 22.2m/s^2

an = v^2/r (given that v = 22.2 and r = 80)

i get an = 6.17m/s^2 and it should be NEGATIVE.

for the vector sum up part...since they are perpendicular to each other, i just find magnitude of two acceleration which is...

sqrt(((-6.17)^2)+(2.78^2)) = 6.77m/s^2

answer is right but just confirming if this is how i should do it.

thank you so much!
 
Last edited:
Yes, that looks right to me.
 
  • #10
ok thank you very much :)
 
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