Calculating Angular Acceleration of a Metal Plate

AI Thread Summary
To calculate the angular acceleration of a metal plate with a mass of 2.00 kg and a pivot point 0.300 m from its center of mass, the moment of inertia can be determined using the parallel axis theorem: I = I_cm + md^2. Given I_cm as 0.210 kg*m², the total moment of inertia can be calculated. The torque (T) acting on the plate is related to the angular acceleration (alpha) by the equation T = I * alpha. By rearranging this equation to alpha = T/I, the angular acceleration can be derived once the torque is known. This approach provides a systematic method for solving the problem.
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Homework Statement



A metal plate in the shape shown has a mass of 2.00kg and hangs from a pivot point located a distance d=0.300m from its center of mass. Its moment of inertia, I_cm, about an axis perpendicular to the plate and passing through the CM is 0.210kg*m2. Calculate the magnitude of the angular acceleration of the plate when theta=0.210 rad.


Homework Equations





The Attempt at a Solution



I'm really not sure where to start. Does anyone have some insight or a guiding principle?
 
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The moment of inertia for a plate about an axis passing through its CM is I_cm=md^2/4. You can also use the parallel axis theorem to calculate the moment of inertia about any other axis: I=I_cm + md^2. Now that you have the moment of inertia, you can use the equation T=I*alpha to calculate the angular acceleration. T is the torque applied to the plate, and alpha is the angular acceleration. T=I*alphaalpha=T/I
 
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