Calculating Angular Distance on a Circular Track with Given Radius and Distance

Thread starter eshock202
Start date Nov 1, 2011
Tags

Angular

AI Thread Summary

To calculate the angular distance on a circular track with a radius of 0.450 km and a distance of 2.54 km run, the formula theta = s/r is used, where s is the arc length. The arc length in this case is 2.54 km, and dividing this by the radius gives an angular distance of 5.65 radians. This calculation confirms that the approach is correct. The solution effectively demonstrates the application of the formula for angular distance. The final answer is 5.65 radians.

Nov 1, 2011

eshock202

Homework Statement

running on a circular track w/ radius of .450 km and runs a distance of 2.54 km. what is the angular distance in radians.

Homework Equations

theta = s/r

The Attempt at a Solution

I assume the 2.54 km would be the arc length? so would the answer just be 2.54/.450 = 5.65 rad?

Physics news on Phys.org

Nov 2, 2011

Delphi51

Homework Helper

Yes.

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...

View full post »

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

View full post »

Thread 'Explain this asphalt sheen'

This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is The second part of the problem is exactly why you get this affect. And one more spoiler:

View full post »