Calculating Average Acceleration for a Slow, Level Turn

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An airplane flying at a constant speed of 1000 km/h changes its direction from west to east over 80 seconds, requiring the calculation of average acceleration. The average acceleration formula used is the change in velocity divided by time. After converting the speed to meters per second, the initial velocity is -277.7 m/s (west) and the final velocity is +277.7 m/s (east), resulting in a change of 555.55 m/s. Dividing this change by the time of 80 seconds yields an average acceleration of 6.94 m/s² to the east. The calculation demonstrates the process of determining average acceleration during a directional change.
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Homework Statement



An airplane flying at a constant speed of 1000 km/h executes a slow, level turn that changes its direction from west to east. If the turn takes 80 s, calculate the plane's average acceleration.


Homework Equations



average acceleration = average velocity/time

The Attempt at a Solution



Its a simple question, but I can't seem to understand how to figure out the average velocity! Can someone please explain it to me? Any help is greatly appreciated :)
 
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Average Acceleration = Change in velocity / time. Let's first convert 1000km/hour to m/s. The answer to that is 277.7 meters/second. Now, we'll define direction (east is positive, west negative). So after it makes the turn, it's velocity is +277.7 m/s. Before it makes the turn, it's velocity is going west, so it's -277.7 m/s. Now, vf - vi = 277.7 - (-277.7) = 555.55 m/s. Now we divide by the time which is 80 seconds to compute the acceleration which is 6.94 m/s^2 to the east.
 
Very clear explination! Thanks for your help, lvslugger36 :)
 
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