Calculating Average Power of a Ski Lift in 2.0 Minutes Using Tension in Cable

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To calculate the average power of a ski lift raising four skiers to a height of 140 m in 2.0 minutes, the total mass of the skiers is 260 kg. The work done against gravity is determined by the potential energy gained, which is 356720 J. Since the lift operates at constant speed, the kinetic energy change is irrelevant, simplifying the calculation. The average power can be calculated using the formula P = Work done / time, leading to the final power output. The discussion highlights that the velocity of the skiers does not impact the average power calculation in this scenario.
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In 2.0 minutes, a ski lift raises four skiers at constant speed to a height of 140 m. The average mass of each skier is 65kg. What is the average power provided by the tension in the cable pulling the lift?

t= 2.0min(60s/1min) = 120s
m = 65kg x 4 = 260kg

Wnc = △Ek + △Ep
Wnc = Ekf - Eki + Epf - Epi
Wnc = -mv^2 + mghf
Wnc = -1/2(v)^2 + 356720J


P = [-1/2(v)^2 + 356720J]/ 120s

i do not know v so i don't know how to solve this. have i made any errors? thanks in advance
 
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From what I can see..the velocity 'v' is irrelevant as there is no change in mechanical energy (constant speed)...you have almost solved it :smile:
 

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