Calculating Average Speed of a Car Round Trip

AI Thread Summary
A car travels uphill at 32 km/h and downhill at 66 km/h, prompting a discussion on calculating average speed for the round trip. The key equation for average speed is total distance divided by total time, but confusion arises due to the absence of specific distance or time values. Participants clarify that the distance uphill equals the distance downhill, allowing for the use of a variable distance to solve the problem. By substituting the distances into the average speed formula, the x values cancel out, simplifying the calculation. The discussion emphasizes the importance of understanding the relationship between speed, distance, and time in solving such problems.
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Homework Statement


A car travels up a hill at a constant speed of 32 km/h and returns down the hill at a constant speed of 66 km/h. Calculate the average speed (in km/h) for the round trip.

Homework Equations



average speed= total distance/ delta time is the only equation i know for it

The Attempt at a Solution



there is no time, or actual distance given in this question, so i got confused and just tried to find the average from adding up the two speeds.. obviously that didn't work- this seems like a really simple problem, so where am i going wrong?
 
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I don't think your doing anything wrong. I think the problem is missing the time information.

Thanks
Matt
 
but... it's online homework. that was just the given problem :/
 
Well, I have solved many dynamics problems and this problem is missing the information needed to solve it. Can you contact the teacher/instructor who posted it?

Thanks
Matt
 
CFDFEAGURU is, I fear, leading you astray. There is no missing fact, although there is a very important word, "returns". That means the distance up the hill is the same as the distance down the hill.
 
Whoops LOL. I missed that word.

Sorry to the OP.

Thanks
Matt
 
But.. it's average speed, not velocity.. so, direction doesn't matter, i thought? and you can't just average the speeds they give you.. and there's no time given :/
 
Suppose the distance is 1km. Work out average speed. 2km? 5km? See a pattern?

Now try x km.
 
so.. like, suppose 1 km is the distance

so do 32 km/hr / 1 km = 32 hr^-1 ,etc?

then what? :/ I'm sorry, i just really need this to be actually taught to me..
 
  • #10
Well, we know that
s=\frac{d}{t}
s=\frac{d_1+d_2}{t_1+t_2}
d1 and t1 are for the first have of the trip @ 32 km/h and d2 and t2 are for the other half at 66km/h.
Now you need to find what each of those are equal to.
 
  • #11
but, how..
 
  • #12
d_1=d_2=x
v_1 = \frac{x}{t_1}
v_2 = x/t_2
Solve for the t's and plug into the speed equation in my last post. Then do some algebra.
 
  • #13
so i have s= 2x/(x/32 + x/66)

but.. if we don't know what s is and we don't know what x is
what comes next?
 
  • #14
s=\frac{2x}{\frac{x}{32}+\frac{x}{66}}
If you find a common denominator for the lowed half of the equation the x's will cancel out.
 
  • #15
yes, of course you're right

thank you very much for your help, i really appreciate it
 
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