Calculating Bandwidth of AM Signal with Dual Cosine Modulation

  • Thread starter Thread starter Shackman
  • Start date Start date
  • Tags Tags
    Bandwidth Signal
AI Thread Summary
The bandwidth of an AM signal can be calculated based on the modulating signal, which in this case consists of two cosine functions at frequencies 70 Hz and 90 Hz. The carrier frequency of 10 kHz does not affect the bandwidth calculation, as it only shifts the signal's spectrum. The bandwidth of the modulating signal is determined by the difference between the highest and lowest frequencies present, which is 20 Hz (90 Hz - 70 Hz). Therefore, the overall bandwidth of the AM signal is twice this value, resulting in a total bandwidth of 40 Hz. Understanding these principles is crucial for accurately calculating the bandwidth of AM signals.
Shackman
Messages
22
Reaction score
2

Homework Statement


What is the bandwidth of an AM signal if the modulating signal is
x(t)=cos(2pi70t)+cos(2pi90t) and the carrier frequency is 10kHz?


Homework Equations





The Attempt at a Solution


The carrier frequency is irrelevant because it just means the signal's spectrum is concentrated around it, it has no bearing on bandwidth. I know that bandwidth of an AM signal is two times the baseband bandwidth. However, I am not sure what that would be here because you are summing cosines with different frequencies. If only one cosine was present, the bandwidth would be two times its frequency, but as there are two I don't know what to do. My guess is that the smaller frequency (larger period) prevails as it would dominate the higher frequency component.
 
Physics news on Phys.org
there are many ways to define "bandwidth." If it means the highest frequency minus the lowest frequency (that is nonnegative), a cosine alone would have 0 bandwidth. Also, two sinusoids would have a bandwidth equal to the frequency of the faster sinusoid minus the frequency of the slower sinusoid.

90 - 70 = 20
 

Similar threads

Back
Top