Calculating Battery Life: Is 0.05 Hours Correct?

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Discussion Overview

The discussion revolves around calculating the battery life for a specific application using a 12V 7Ah battery to power a 1700W load. Participants explore the methodology for determining battery duration and consider various factors that may affect the calculation.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant calculates the battery life as 0.05 hours based on the formula Time = 7Ah / 141.7A, questioning the correctness of this approach and whether other factors should be considered.
  • Another participant warns that drawing 141A from the battery could lead to dangerous outcomes, such as overheating or battery failure, due to internal resistance and heat generation.
  • A different participant emphasizes that the battery's rating indicates it can provide 7A for one hour, suggesting a need to calculate the current requirement for the 1700W appliance using P=V^2/R.
  • One participant shares an example of a lithium-ion battery powering a 20W bulb, illustrating a different method of calculation that leads to a practical battery life estimate, while also asserting that resistance calculations are unnecessary for their example.
  • Another participant provides an alternative calculation method, converting amp-hours to energy in joules and then determining time based on power, arriving at a significantly shorter duration of 14 seconds.

Areas of Agreement / Disagreement

Participants express differing views on the methodology for calculating battery life, with no consensus reached on the correct approach. Some participants challenge the initial calculation and propose alternative methods, while others defend their reasoning.

Contextual Notes

Participants highlight limitations in the initial calculation, including the neglect of internal resistance and safety concerns when drawing high currents. The discussion also reflects varying interpretations of battery ratings and energy calculations.

Who May Find This Useful

This discussion may be useful for individuals interested in battery technology, electrical engineering, or those seeking to understand practical applications of battery life calculations in real-world scenarios.

JD88
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I am trying to determine how long a particular battery will last for my application.

These numbers are just for an example.

Battery stats:
12 V 7 Ah

Application
1700 W

Power=Current*Voltage
1700W = Current * 12V
Current=141.7A

Time = 7Ah / 141.7A
Time = 0.05 hours

Is this correct, or are there other factors that I must consider?
 
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JD88 said:
Time = 7Ah / 141.7A
Time = 0.05 hours

Is this correct, or are there other factors that I must consider?
That the wires would melt and the battery would explode if you could pull 140A from it.

Batteries have an internal resistance due to the chemistry - think of it as a small resistor in series with the battery.
As you draw a current, the resistance creates a voltage difference and so the voltage coming out of the battery drops, the current flowing through the resistance also generates heat in the battery.
For a lead acid battery this resistance is very low so you can get a very large current from a lead acid battery - but this doesn't mean that it is safe.
 
I don't care about the numbers from my example. Just the procedure. Is that how I would go about determining how long the battery would last?
 
The battery rating, 12V 7Ah, means that 7 amps can be drawn from the battery at 12 volts for an hour, this is its energy content.

For an appliance rated at 1700W, you need to calculate its resistance at its rated voltage, ie use P=V^2/R. Calculate the current requirement. Now 7 amps for 1 hr = x amps for y hrs!
Or
Directly use energy balance.
 
Last edited:
Sorry your method has confused me.

An example. A lithium ion battery rated at 4.4Ah powers a 20W bulb at 14.4V

20W/14.4V = 1.39A 4.4Ah/1.39A = 3.17hrs

These are the specifications of my mountain bike lights. They do run for approximatley 3.2 hours before the world goes dark and I am walking back to my car blind. Its dark in Thetford Forest when moon is new.

No resistance needed to work this out. Also if you follow your resistance method the current works out to be 141.7A. The same as JD88's answer. So your method is just a more complicated way of getting to same answer!

JD88 you are right!
 
The amp hours is the total energy available in the battery.

7 Ahr *(3600s/hr) = 25200 Asec

power = energy / time

time = energy/power

time = 25200 Asec / 1700 W

time = 14 Sec
 

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