Calculating Biconvex Glass Lens Radius of Curvature for a +35-cm Focal Length

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To calculate the radius of curvature for a biconvex glass lens with a +35-cm focal length and a refractive index of 1.70, the formula 1/f = (n-1)(1/r1 + 1/r2) is used, where r1 and r2 are the radii of curvature. The user calculated the radius to be 50 cm, seeking confirmation of the accuracy. The discussion highlights the importance of posting such questions in the appropriate forum, specifically under "Homework and Coursework Questions." The calculation appears correct, but the context of the question is noted as potentially more suitable for a different section. Accurate understanding of lens formulas is crucial for optics-related inquiries.
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Question: A biconvex glass (n = 1.70) thin lens is to have a +35-cm focal length. If the radius of curvature of each surface is measured to be the same, what must it be? Give your answer in cm to two decimal places.

My answer:
I used this equation 1/f=(n-1)*(1/r1+1/r2), I got an answer 50cm. Am I right or I missing somthings? still doubt
 
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I think this should be in the homework question section.
 
Thanks richyw
 
Indeed, questions like this (solutions to specific exercises, whether they are actually assignments for a course or not) belong in one of the "Homework and Coursework Questions" forums. In this case, the "Introductory Physics" is the appropriate one.
 
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