Calculating BJT Base Current with Zener Diode

AI Thread Summary
The base current of a BJT connected to a zener diode is influenced by the emitter current, following the relationship I_E = β I_B, and is not directly dependent on the zener. The zener functions as a shunt regulator, maintaining a stable voltage at the base as long as sufficient current is drawn. The ability of the zener to hold its specified voltage, such as 5.6V, relies on the resistor R1, the emitter current, and the transistor's beta. If the emitter current is too high, it can lead to a voltage drop across R1, causing the output voltage to decrease. Understanding these dynamics is crucial for accurate calculations in BJT circuits with zener diodes.
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What is the BJT base current if the base is connected to a zener diode like in the circuit here - http://www.satcure-focus.com/tutor/page5.htm
With a voltage divider it's thevenin's equivalent. But with zener, should I consider it as a voltage source?
 
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likephysics said:
What is the BJT base current if the base is connected to a zener diode like in the circuit here - http://www.satcure-focus.com/tutor/page5.htm
With a voltage divider it's thevenin's equivalent. But with zener, should I consider it as a voltage source?

Base current depends on the emitter current you are drawing I_E=\beta I_B\;, it does not depend on the zener. Think of the zener as a shunt regulator. The zener draw enough current to keep the zener voltage at the base. Whether the zener can hold 5.6V depend on the R1 and emitter current and the beta of the transistor. If you draw too much current at the emitter and the base current is high enough that the R1 drop more voltage, then the output voltage will go down.

The zener is a shunt regulator.
 
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