Calculating Centripetal Acceleration & Force in Two Cars

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Two cars, A and B, are traveling at 28 m/s on a curve with a radius of 124 m, with masses of 1080 kg and 1500 kg, respectively. The centripetal acceleration for both cars can be calculated using the formula a = v²/r, yielding approximately 6.16 m/s² for both vehicles. The centripetal force can be determined using F = m * a, resulting in 6665.2 N for Car A and 9240 N for Car B. The discussion notes that the angle of banking is not provided, so the curve is assumed to be flat, with centripetal force supplied by friction. The frictional force can be equated to the centripetal force to find the coefficient of static friction.
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Two cars are traveling at the same speed of 28 m/s on a curve that has a radius of 124 m. Car A has a mass of 1080 kg, and car B has a mass of 1500 kg. Find (a) the magnitude of the centripetal acceleration and (b) the magnitude of the centripetal force for Car A, (c) the magnitude of the centripetal acceleration and (d) the magnitude of the centripetal force for Car B.

I used the formula V=sqrt(rg tan theta)
for part a: v=sqrt(151*9.80 tan theta)
For part b: v=sqrt (115*9.80 tan theta)

But how would i find theta?
 
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Why do you think the curve is banked? The centripetal acceleration doesn't depend on the banking angle anyway. What's the centripetal acceleration of an object moving at velocity v on a curve of radius r?
 
In the problem the angle of banking is not given. So assume it as flat.
On the flat curve, the centripetal force is provided by the frictional force.
For car A, what is the frictional force? You know the centripetal force.
Equating them you can find the μs. Using this you can solve the second part.
 

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