Calculating Charge, Current, and Energy in a Simple RC Circuit

AI Thread Summary
In a simple RC circuit with a capacitor of 1x10^{-6}F, a resistor of 2x10^{6} Ohm, and a 10V battery, the charge on the capacitor after 10 seconds is calculated using the formula Q = C * E * (1 - e^{(-t)/R*C}), resulting in approximately 9.932x10^{-6} C. The current through the resistor is given by I = E/R * e^{(-t)/R*C}, yielding about 3.37x10^{-8} A. Discussions on calculating the rate of energy stored in the capacitor and the energy supplied by the battery emphasize the need to express energy in terms of charge and to consider power definitions. The total energy stored in the capacitor is calculated as U = 1/2 * E^2 * C, but this does not reflect the rate of energy storage during charging. The conversation highlights the importance of understanding the exponential charging process and the correct application of power equations in RC circuits.
Apprentice123
Messages
92
Reaction score
0
The values of components in a simple RC circuit in series with a key are: C = 1x10^{-6}F, R=2x10^{6} Ohm and epsilon = 10 V. 10s at the moment after the key is closed, calculate:

a) the charge in capacitor
b) the current in the resistor
c) the rate at which energy is stored in capacitor
d) the rate at which energy is supplied by the battery


My solution:

a) Qmax = C * epsilon = 1x10^5 c

b) I = - dQ/dt
Rule of Kirchhoff
I*R = Q/C
I = Q / R*C = 5x10^{-6} A

c) How to calculate?
d) How to calculate?
 
Physics news on Phys.org
Apprentice123 said:
The values of components in a simple RC circuit in series with a key are: C = 1x10^{-6}F, R=2x10^{6} Ohm and epsilon = 10 V. 10s at the moment after the key is closed, calculate:

a) the charge in capacitor
b) the current in the resistor
c) the rate at which energy is stored in capacitor
d) the rate at which energy is supplied by the battery


My solution:

a) Qmax = C * epsilon = 1x10^5 c

b) I = - dQ/dt
Rule of Kirchhoff
I*R = Q/C
I = Q / R*C = 5x10^{-6} A

c) How to calculate?
d) How to calculate?

Maybe consider:
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/filter.html#c2
 
Apprentice123 said:
thanks, but I could not resolve the (c) and (d)

Well, what is the "rate of energy build up"?
 
Apprentice123 said:
thanks, but I could not resolve the (c) and (d)

Nevermind (c) and (d), your answers for (a) and (b) are not correct yet.

LP is reminding you that there is a time constant associated with the RC circuit, and that the charging is exponential with time. You need to write the equation for the capacitor voltage as a function of time, and use that equation to solve for a-d.
 
berkeman said:
Nevermind (c) and (d), your answers for (a) and (b) are not correct yet.

LP is reminding you that there is a time constant associated with the RC circuit, and that the charging is exponential with time. You need to write the equation for the capacitor voltage as a function of time, and use that equation to solve for a-d.

Yes. New:

a) Q = C * E * (1 - e^{(-t)/R*C}
Q = 9,932x10^{-6} c


b) I = E/R * e^{(-t)/R*C}
I = 3,37x10^{-8} A

(c) and (d) I not find equation
 
Apprentice123 said:
Yes. New:

a) Q = C * E * (1 - e^{(-t)/R*C}
Q = 9,932x10^{-6} c


b) I = E/R * e^{(-t)/R*C}
I = 3,37x10^{-8} A

(c) and (d) I not find equation

c) the rate at which energy is stored in capacitor
d) the rate at which energy is supplied by the battery

What is the definition of power, in terms of energy? What is the power dissipated in a resistor in terms of I and V? How is the energy stored on a capacitor defined?
 
berkeman said:
What is the definition of power, in terms of energy? What is the power dissipated in a resistor in terms of I and V? How is the energy stored on a capacitor defined?

Energy in a capacitor charged:

1/2 * C * V^2
 
Apprentice123 said:
Energy in a capacitor charged:

1/2 * C * V^2

Since you already found a relationship between charge and time and another between charge flow rate (i.e. current) and time, it's wise to express energy in terms of charge. Then you can use calculus to find the equation for power.
 
  • #10
ideasrule said:
Since you already found a relationship between charge and time and another between charge flow rate (i.e. current) and time, it's wise to express energy in terms of charge. Then you can use calculus to find the equation for power.

c)
U = 1/2 * E^2 * C
U = 5x10^{-5}J

d)
E = (Q*E)/(t)
E = 1x10^{-5}J


It is correct ?
 
  • #11
Apprentice123 said:
c)
U = 1/2 * E^2 * C
U = 5x10^{-5}J

d)
E = (Q*E)/(t)
E = 1x10^{-5}J


It is correct ?

Part (c) is not correct. What you have calculated is the total energy stored in the capacitor (after it has charged fully). The question is asking for the *rate* at which energy is stored (during the charging process)

For part (d), I would follow berkeman's advice in his latest post and investigate power.
 
  • #12
I meant that you should express, for part c), the energy stored on the capacitor in terms of the charge on the capacitor.
 

Similar threads

Replies
4
Views
1K
Replies
5
Views
7K
Replies
5
Views
2K
Replies
2
Views
2K
Replies
4
Views
2K
Replies
4
Views
2K
Replies
5
Views
2K
Replies
6
Views
2K
Back
Top