Calculating Charge on a Parallel Plate Capacitor

AI Thread Summary
A 5800-nF parallel plate capacitor connected to a 14-V battery has a charge calculated using the formula C = Q/V. The calculation shows that Q equals 14 V multiplied by 5800 nF, resulting in 81200 nC. The positive plate holds a net charge of +Q, while the negative plate has -Q. The initial answer was deemed incorrect due to the requirement for scientific notation. The correct charge is 8.12 x 10^4 nC.
Cisneros778
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Homework Statement


A 5800-nF parallel plate capacitor is connected to a 14-V battery and charged.
What is the charge Q on the positive plate of the capacitor?

Homework Equations


C = Q/V

The Attempt at a Solution


This looks like a very simple question. The capacitor is fully charged so 5800 nF = Q/(14 V)
14 V x 5800 nF = 81200 nC

The positive plate will have a +Q net charge and -Q net charge will be on the negative plate.
My answer is incorrect though.
 
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Sorry I am doing this from my iPad. My answer is correct it wanted the answer in scientific notation. Thanks anyways
 
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