Calculating Circuit Resistance: Regular Hexagon Wire with Diagonal Resistance

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The discussion revolves around calculating the current in a circuit powered by a 10V battery, where the resistance is formed by a regular hexagon with all diagonals drawn, each segment having a resistance of R. The user seeks assistance in determining the effective resistance and current, expressing difficulty in identifying series and parallel connections among the resistors. They mention the challenge of recognizing points with the same potential, which is crucial for simplifying the circuit. There is a request for a more detailed explanation and the possibility of a diagram to clarify the circuit configuration, as the user is uncertain about the specific arrangement being discussed.
mercury
hey i have a problem with effective reisitance of a circuit

what is the current in a circuit containing a 10V battery , the resistance consists of a wire in the shape of a regular hexagon (all sides equal) with all the diagonals drawn. each side of the hexagon and each portion of the diagonal has a resistance R .
(say the hexagon is ABCDEF and O is the pt. of intersection of all the diagonals then resistance of AB = resistance of BC= ...= resistance of OA = resistance of OC ...)
i hope u understand..i would display a diagram if i could..but right now i am not able to..nevertheless , would appreciate any help.
 
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try to rearrange all the resistors
just like with a cube of resistors, where you end up with (R//R//R)+(R//R//R//R//R//R)+(R//R//R)
 
do u mean..that i should try and figure out series and parallel connections..if that's what u mean..i did try.but i was'nt able to identify pts. having the same potential ,which is what one ought to do...isn't it ?

is there anyway u could explain what should be done a little more in detail?
thanks in advance
 
what you said is what i meant, i am not good in that solving that kind of problems
but if you can make a picture maybe i can help, am now in doubt whoich circuit you mean i can think of 2 different circuits now
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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