Calculating Coefficient of Friction for a Crate on an Inclined Surface

AI Thread Summary
To calculate the coefficient of friction for a 225 kg crate on a 20-degree incline, a horizontal force of 535 N is required to initiate movement down the slope. The solution involves applying Newton's laws of motion to determine the frictional force (Ftr). The correct coefficient of friction is calculated to be 0.665. A miscalculation was noted, leading to confusion, but the final answer aligns with the expected result. Accurate calculations are crucial in solving physics problems involving inclined surfaces and friction.
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Homework Statement


A 225 kg crate rests on a surface that is inclined above the horizontal at an angle of 20o.
A horizontal force (F = 535 N parallel to the ground, not the incline) is required to start the crate moving down the incline. What is the coefficient of friction between the crate and the incline?

P.S. Ftr is a frictional force.

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Homework Equations


Newton's laws of motion.

The Attempt at a Solution


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It doesn't work.
The answer must be 0.665 .[/B]
 
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Funny. That's exactly what I get. What is ##\cos\alpha## on your calculator ?
 
I missed one number xD. Sorry for wasting your time.
 
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