Calculating Coefficient of Friction for Moving a Piano

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To calculate the coefficient of friction for moving a 1,000-N piano with a horizontal force of 350 N, the formula Ff = (mu)Nf is used, where Ff is the force of friction and Nf is the normal force. Since the piano is moved at a constant speed, the applied force equals the frictional force. Dividing the applied force by the weight of the piano gives the coefficient of friction: 350 N / 1,000 N = 0.35. This indicates that the coefficient of friction is 0.35, which is sufficient for the problem's requirements. Understanding this calculation is essential for determining the necessary force to move heavy objects like pianos.
xyril1325
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can anyone show me the solution in this problem:

A 1,000-N piano is moved 20 meters across a floor by a horizontal force of 350 N. Find the coefficient of friction.
 
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You show us how you tried to solve the problem. Then you'll get plenty of help.
 
first, i just divide them, 350/1000=coefficient of friction coz the formula was Ff=(mu)Nf
 
xyril1325 said:
first, i just divide them, 350/1000=coefficient of friction coz the formula was Ff=(mu)Nf
That's all there is to it. (Assuming that the 350 N force moves the piano at a constant speed.)
 

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