Calculating Concentrations in a 1.0-L Buffer Solution with Added HCl

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To determine the concentrations of HNO2 and NaNO3 in a 1.0-L buffer solution after adding 1.8 g of HCl, the initial concentrations were 0.105 M for HNO2 and 0.180 M for NaNO3. The addition of 1.8 g of HCl equates to approximately 0.0494 mol, which affects the buffer's pH and the concentrations of the components. The correct approach involves careful calculation of the changes in concentrations rather than simple subtraction or addition. The final concentrations after adjusting for the HCl addition were confirmed to be different from the initial calculations, highlighting the importance of accurate mathematical execution. This discussion emphasizes the need for precise calculations in buffer solution chemistry.
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Homework Statement


A 1.0-L buffer solution is 0.105 M in HNO2 and 0.180 M in NaNO3. Determine the concentrations of HNO2 and NaNO3 after addition of 1.8 g HCl.

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The Attempt at a Solution


I turned 1.8 g of HCl into mols and got 0.0494 mol of HCl. I subtracted this number from .105 M to find the new concentration of HNO2 and got 0.154 M. For NaNO3 I added 0.0494 and got 0.229 M but these answers were wrong. So what is the process to solve this problem?
 
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Technically speaking HNO2/NO3- mixture is not a buffer.
 


It's supposed to be NaNO2.
 


Ki-nana18 said:
got 0.0494 mol of HCl. I subtracted this number from .105 M (...) and got 0.154 M.

Check your math and pay more attention to what you add/subtract. Idea is - in general - OK, but the execution is horrible.
 


I got the right answers, thank you for your help. :approve:
 
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