Calculating Constant Speed of a Train with Variable Acceleration

  • Thread starter Thread starter astrololo
  • Start date Start date
  • Tags Tags
    Speed Train
AI Thread Summary
A train starts at 0 m/s, accelerates over 60 m, maintains a constant speed for 120 m, and decelerates over 30 m, completing the journey in 25 seconds. The initial equations provided focus on the acceleration phase but do not encompass the entire trip. To find the constant speed, it’s essential to develop equations for each segment of the journey, including acceleration, constant speed, and deceleration. The discussion emphasizes the need for a comprehensive approach rather than isolated equations. A complete analysis of all phases is necessary to accurately determine the train's constant speed.
astrololo
Messages
200
Reaction score
3

Homework Statement


A train is at 0 m/s at the begining. It accelerates on a distance of 60 m, after it goes on a constant speed on the next 120 m and it finally decelerates on the next on 30 m and stops. The whole traject is 25 sec. Find the constant speed.

Homework Equations



x final = x initial + v initial * t + 1/2 * a * t^2

The Attempt at a Solution



60 = 0 + 0 + 1/2* a* t^2

60 = 1/2 * a * t^2

We also know that the first traject goes from 0 to 60 m and from 60 to 180 m and finally from 180 to 210 m.
 
Physics news on Phys.org
astrololo said:

Homework Statement


A train is at 0 m/s at the begining. It accelerates on a distance of 60 m, after it goes on a constant speed on the next 120 m and it finally decelerates on the next on 30 m and stops. The whole traject is 25 sec. Find the constant speed.

Homework Equations



x final = x initial + v initial * t + 1/2 * a * t^2

The Attempt at a Solution



60 = 0 + 0 + 1/2* a* t^2

60 = 1/2 * a * t^2

We also know that the first traject goes from 0 to 60 m and from 60 to 180 m and finally from 180 to 210 m.
Writing down a couple of equations is not a valid attempt at solution. For this problem, you must examine all the parts of the trip in order to determine the constant speed of the train.
 
SteamKing said:
Writing down a couple of equations is not a valid attempt at solution. For this problem, you must examine all the parts of the trip in order to determine the constant speed of the train.
Yeah I know but I have no idea on what to do next... I wrote down 3 equations for each part of the traject but after that I have no idea...
 
astrololo said:
Yeah I know but I have no idea on what to do next... I wrote down 3 equations for each part of the traject but after that I have no idea...
You wrote down an equation covering the first part of the trip. Don't you think you should write some additional equations describing the other parts of the same trip?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top