CaptainMarvel
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Using the FRW:
<br /> \left( \frac {\dot{a}} {a} \right)^2 = \frac {8 \pi G \rho} {3} - \frac {k c^2} {a^2}<br />
We define critical density by setting k = 0 and rearranging to get:
<br /> \rho_c = \frac {3 H^2} {8 \pi G}<br />
Where:
<br /> H = \left( \frac {\dot{a}} {a} \right)<br />
My question is does \rho include the density contribution for Cosmological Constant (dark energy) \Lambda or is this derivation only for a Universe with no cosmological constant?
How does one then actually measure the density of Universe?
I know that the density has been measured to be slightly less than the critical density, but I thought we are meant to live in a flat Universe? Is this due to the cosmological constant and how is this reconciled with \rho not being exactly \rho_c?
Finally, I am right in saying that a Universe with \rho_c will stop expanding after infinite time, one with \rho > \rho_c will collapse back on itself and one with \rho < \rho_c will expand forever?
Many thanks.
<br /> \left( \frac {\dot{a}} {a} \right)^2 = \frac {8 \pi G \rho} {3} - \frac {k c^2} {a^2}<br />
We define critical density by setting k = 0 and rearranging to get:
<br /> \rho_c = \frac {3 H^2} {8 \pi G}<br />
Where:
<br /> H = \left( \frac {\dot{a}} {a} \right)<br />
My question is does \rho include the density contribution for Cosmological Constant (dark energy) \Lambda or is this derivation only for a Universe with no cosmological constant?
How does one then actually measure the density of Universe?
I know that the density has been measured to be slightly less than the critical density, but I thought we are meant to live in a flat Universe? Is this due to the cosmological constant and how is this reconciled with \rho not being exactly \rho_c?
Finally, I am right in saying that a Universe with \rho_c will stop expanding after infinite time, one with \rho > \rho_c will collapse back on itself and one with \rho < \rho_c will expand forever?
Many thanks.
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