Calculating Current Density of Protons in Solar Wind at Earth | 691 km/s

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The density of protons in the solar wind near Earth is 10.0 cm^-3, with a speed of 691 km/s. To calculate the current density, the formula used is (nLA)e, where n is the proton density converted to 1 E7 m^-3, and e is the elementary charge (1.6E-19 C). The calculated current density is approximately 1.11 E-7 A/m². To find the total current in amperes received by Earth, this current density is multiplied by the cross-sectional area of Earth, resulting in about 8.82 E12 amperes. The calculations confirm the current density and total current values for protons in the solar wind.
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Near earth, the density of protons in the solar wind is 10.0cm^-3, and their speed is 691 km/s.
a) find current density of these protons
b) what current in amperes does Earth recieve




a. To find the current density I need to multiply (nLA)e
then after i get I divide it by A


The Attempt at a Solution



To find the current density I need to multiply (nLA)e

do i need to convert 10.0 protons cm^-3 to 10000000m^-3 because i tried that and it didnt work?
I guess my main question is do i have the conversions right:
v= 691000 m/s
n = 1 E7
e= 1.6E-19
the final answer i got was 1.11 E-7 (is this answer maybe negative?)
 
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b. To find the current in Amperes that Earth recieves I multiply the current density by the area:1.11E-7 * 4*π*(6.371E6)^2 = 8.82E12 amperes
 

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