Calculating Current for 1.5T in Solenoid

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SUMMARY

The discussion focuses on calculating the current required to achieve a magnetic field strength of 1.5 Tesla in a solenoid that is 1.8 meters long and 75 centimeters in diameter, using wire with a diameter of 2 millimeters. The relevant equation provided is N=2πR/L, where R is the radius of the solenoid and L is the length of the wire. Participants are seeking assistance in determining the number of turns that can be made with the given wire length and diameter to solve for the required current.

PREREQUISITES
  • Understanding of solenoid physics and magnetic fields
  • Familiarity with the formula N=2πR/L
  • Basic dimensional analysis skills
  • Knowledge of wire specifications and their impact on solenoid design
NEXT STEPS
  • Calculate the number of turns in the solenoid using the formula N=2πR/L
  • Research the relationship between current and magnetic field strength in solenoids
  • Explore the impact of wire diameter on the solenoid's performance
  • Learn about the Ampere's Law and its application in solenoid calculations
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Physics students, electrical engineers, and anyone involved in designing or analyzing solenoids and magnetic field applications.

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Homework Statement



Solenoid is 1.8m long and 75 cm in diam. one layer tightly wound with wire that has diam 2mm. what current needs to run thru to get 1.5T

Homework Equations


N=2piR/(L) where R is radius of solenoid and L is wire lenght


The Attempt at a Solution


Once I find how many rolls I can solve the problem. I need help finding this
 
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How many times does 2 mm go in 1.8 m? Or think of it in terms of dimensional analysis. You've got 1turn/2mm.
 

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