Calculating Current in a Wire of Given Dimensions

AI Thread Summary
A wire with a radius of 1.2mm carrying a current of 3.2A has a calculated electron drift velocity of approximately 0.177 m/s, based on the provided electron density of 2.5x10^25 electrons per cubic meter. However, this electron concentration is considered low for a metal wire, which typically ranges from 10^28 to 10^29 electrons per cubic meter. A correction was noted regarding the cross-sectional area calculation, which should be 4.5x10^-6 m² instead of 4.5x10^6 m², but this typo does not impact the final drift velocity result. The discussion also raised a question about how doubling the wire's cross-sectional area would affect the drift velocity. Overall, the calculations and assumptions about electron density in the wire material are crucial for accurate current and drift velocity assessments.
Johnahh
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Homework Statement


a wire carrying a current of 3.2A has a radius of 1.2mm. the material of the wire has 2.5x10^25 free electrons per cubic metre. the elementary charge is 1.6x10^-19


Homework Equations


I=Anev
cross section = pi*r^2



The Attempt at a Solution


pi*0.0012^2 = 4.5x10^6

3.2/4.5x10^6*2.5x10^25*1.16x10^-19 = 0.1777 recurring
I am sure this is not correct as it seems to fast, I have seen some examples and they are more like 2.8x10^-4 m/s
Am i supposed to make 2.5x10^25 into 2.5x10^19 for mm^3 instead of m^3?
Any help please?
 
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2.5 x10^25 electrons per cubic metre is very low value for a metal wire. It should be in the range 10^28-10^29 electron/m^3.

ehild
 
you have the cross sec area as 4.5x10^6 ...it should be 4.5x10^-6... this is just a typing error and does not affect your answer.
For the figures you have given I also get 0.177
I agree with ehild regarding electron concentration for a metal. 10^28 to 10^29
 
Yeah it was a typo sorry. OK so the electron drift is 0.177 m/s. What happens if the cross section doubles in size is it v*2 or v/2? Thanks
 
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