Calculating Curve Line in a Graph: An Example

AI Thread Summary
To calculate the curve line in a graph, the equation v = d/t is referenced, but clarity on the graph's axes and data representation is crucial. The initial graph lacks proper labeling and combines three different data sets on the same vertical scale, leading to confusion. The discussion shifts to the trajectory of a skier, emphasizing that the slope of the hill and forward velocity significantly affect the dynamics of a fall. Personal experiences highlight that time, speed, and distance computations are not typically applied in skiing scenarios. Understanding the relationship between slope and velocity is essential for accurate analysis.
Pin Head
Messages
23
Reaction score
0
Hi,
Ho do I calculate for the curve line in this graph I understand that I use this equation
v = d/t.Could anyone show me an example?
 

Attachments

  • trajectory.JPG
    trajectory.JPG
    10.8 KB · Views: 419
Physics news on Phys.org
Pin Head said:
Hi,
Ho do I calculate for the curve line in this graph I understand that I use this equation
v = d/t.Could anyone show me an example?

Your graph is meaningless. The axes are not labelled, but more importantly, you're plotting 3 different things all with the same vertical scale! It makes no sense.

Zz.
 
Hi sorry about that unfortunately I've had to design these diagrams in paint so they are not that accurate , but what I would like to know is about the line that curves which is title trajectory,The other thing is is that the diagram that made no sense was from a physics example I was gave to use So hopefully the diagrams I've made make a bit more sense
 

Attachments

  • acceleration.JPG
    acceleration.JPG
    4.9 KB · Views: 459
  • trajectory.JPG
    trajectory.JPG
    6.6 KB · Views: 397
  • velocity.JPG
    velocity.JPG
    7 KB · Views: 415
here, let me google that for you: http://www.engineeringtoolbox.com/accelaration-gravity-d_340.html" .
 
Last edited by a moderator:
But what does this have to do with a skier falling down. I rarely do a time, speed distance computation when I fall while skiing. However, based on some personal experience, the hill's slope has a significant impact on the dynamics of the fall. Also the forward velocity (or more correctly the velocity along the skiing surface) influences the the dynamics. Unless this is associated with jumping, the velocity normal to the surface, which is typically at a significant angle to the horizontal, is fairly low.
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top