Calculating Distance & Energy for Explosion to Moon

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To hit the moon with a bullet, it would need to travel at approximately 11.2 km/s, accounting for atmospheric effects. The discussion highlights that the bullet's speed is critical, and factors like terminal velocity must be considered. For causing an explosion to reach the moon, the required energy in kilojoules (KJ) depends on various factors, including the explosion's radius, which needs empirical determination. The conversation emphasizes that the distance from Earth significantly impacts the energy needed for such an explosion. Overall, precise calculations involve complex physics and numerous variables.
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ok just a couple of questions I have been thinking about.. this is not my area of expertise so help would be greatly appreciated

Could anyone tell me how far away from Earth I would have to be before I could shoot a bullet from a gun that would hit the moon. Supposing the bullet could travel at 1000 m/s.. is there a formula I could use?

And suppose I had a metal indestructable box and could cause and explosion 100,000 + feet above the earth, how many KJ would I need to produce to send it within the moons gravitational pull?

Also if the same experiment was done at around 36,000 miles above the Earth how many K/J would need to be created?

Any help would be fantastic :D
 
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The bullet would need to be traveling around 11.2 thousand m/s when it leaves the nozzle in order to hit the moon if we had no atmosphere. With atmosphere you must account for the terminal velocity as well.

http://en.wikipedia.org/wiki/Escape_velocity

The energy of the explosion may be proportional to how large it would need to be to reach the moon, however the radius of the explosion is what matters, that would have to be empirically determined as there is too many variables.

Good luck on your mission to destroy the moon.
 
thanks a lot for the info
 
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