Calculating Distance Traveled: Police Chase Scenario

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AI Thread Summary
To solve the police chase scenario, the distance traveled by both the speeding car and the trooper must be calculated. The car moves at a constant speed of 129 km/hr, which converts to approximately 35.83 m/s. The trooper accelerates from rest at 2.7 m/s², and the relevant equation for distance is d = v(initial)t + 0.5at². The key is to find the time when both the trooper and the car cover the same distance, requiring the setup of equations for both their positions. Understanding the relationship between their speeds and acceleration is crucial for determining when the trooper overtakes the car.
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Homework Statement



A car traveling at a constant speed of 129 km/hr passes a trooper hidden behind a billboard. One second after the speeding car passes the billboard, the trooper sets in a chase after the car with a constant acceleration of 2.7 m/s2. How far does the trooper travel before he overtakes the speeding car?



Homework Equations



d= v(initial)t + .5at^2


The Attempt at a Solution



d= 35.83m/s(t) + .5(2.7)(t)^2 + 35.83

I don't understand what needs done, thanks
 
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What is the position of the trooper at time t?

What's the position of his target at time t?

When are they in the same place?
 

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