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I guess I missed that.Rumplestiltskin said:I've also already worked that out as 0.5 * 10 * 52 = 125m.
I'd stand by that. Why do you ask?
Huzzah!
You're the man!
The discussion centers on calculating the distance traveled by a car under uniform acceleration, specifically focusing on the distance covered during the fifth second of its journey after it has traveled 15 meters in the second second. The correct approach involves using the equation of motion, d(t) = 0.5 * a * t^2, to derive the distance for each second and find the acceleration. The participants clarify that the car starts from rest, and the initial velocity for the second second is derived from the acceleration calculated from the distance covered in the second second.
PREREQUISITESStudents studying physics, particularly those focusing on kinematics, as well as educators seeking to clarify concepts of uniform acceleration and motion equations.
I guess I missed that.Rumplestiltskin said:I've also already worked that out as 0.5 * 10 * 52 = 125m.
I'd stand by that. Why do you ask?
Huzzah!