Calculating drop heights based on known forces

  • Thread starter Thread starter robwrightham
  • Start date Start date
  • Tags Tags
    Drop Forces
AI Thread Summary
To calculate the drop height for a 12kg object to match the force of an air piston, one must consider the force exerted, the time period of that force, and the deceleration distance after impact. The time period can be calculated, but the deceleration distance requires additional data, such as the object's material properties and the surface it impacts. Understanding the relationship between force, mass, and acceleration is crucial, typically using Newton's second law (F=ma). The discussion emphasizes the need for precise measurements to ensure accurate calculations. Properly determining these variables will allow for the calculation of the necessary drop height.
robwrightham
Messages
4
Reaction score
0
I have a fixed object of known mass (12kg) being impacted by an air pistion of known force (), I desperatly need to be able to calculate what height an object would have to be dropped to have the same force imparted to it that a specific known piston would.
what equations do i use and what other data do i require?
 
Physics news on Phys.org
You need to know the time period the force is acting and the distance on which the object decelerates after dropping.
 
haael said:
You need to know the time period the force is acting and the distance on which the object decelerates after dropping.

the time period is easily calculated, but what do you mean by "distance on which the object decelerates after dropping" how do i calculate this?
 
Thread 'Gauss' law seems to imply instantaneous electric field'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...
Back
Top